2x^2+10x+10.5=0

Solution for 2x^2+10x+10.5=0 equation:

2x^2+10x+10.5=0

a = 2; b = 10; c = +10.5;
Δ = b2-4ac
Δ = 102-4·2·10.5
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-4}{2*2}=\frac{-14}{4}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+4}{2*2}=\frac{-6}{4}
=-1+1/2
$